Question 277629: The number of accidents that occur at the intersection
of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The number of accidents that occur at the intersection
of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
----------------------
The Graph.
Put 0,1,2,3 on the horizontal axis
Plot the probabilities as the y-values associated with 0,1,2,3
-------------------------------------------
E(x) = 0*0.84+1*0.13+2*0.02 + 3*0.01
= 0 + 0.13 + 0.04 + 0.03
= 0.21
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Cheers,
Stan H.
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