SOLUTION: Using the FOIL method how would you multiply this binomials (3x - 2 ) it's squared on the outside of the last parenthesis.

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Question 277297: Using the FOIL method how would you multiply this binomials (3x - 2 ) it's squared on the outside of the last parenthesis.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%283x-2%29%5E2 Start with the given expression


%283x-2%29%283x-2%29 Expand. Remember something like x%5E2=x%2Ax


Now let's FOIL the expression



Remember, when you FOIL an expression, you follow this procedure:


%28highlight%283x%29-2%29%28highlight%283x%29-2%29 Multiply the First terms:%283x%29%2A%283x%29=9x%5E2


%28highlight%283x%29-2%29%283x%2Bhighlight%28-2%29%29 Multiply the Outer terms:%283x%29%2A%28-2%29=-6x


%283x%2Bhighlight%28-2%29%29%28highlight%283x%29-2%29 Multiply the Inner terms:%28-2%29%2A%283x%29=-6x


%283x%2Bhighlight%28-2%29%29%283x%2Bhighlight%28-2%29%29 Multiply the Last terms:%28-2%29%2A%28-2%29=4


9x%5E2-6x-6x%2B4 Now collect every term to make a single expression



9x%5E2-12x%2B4 Now combine like terms


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Answer:
So %283x-2%29%5E2 foils and simplifies to 9x%5E2-12x%2B4

In other words, %283x-2%29%5E2=9x%5E2-12x%2B4