SOLUTION: Hi my question is how do I simplify: y = 2({{{x^lnx}}}) ? I took the ln of both sides and I tried bringing the lnx down by properties of log so I ended up with: lny = lnxln2x

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi my question is how do I simplify: y = 2({{{x^lnx}}}) ? I took the ln of both sides and I tried bringing the lnx down by properties of log so I ended up with: lny = lnxln2x       Log On


   

Question 277178: Hi my question is how do I simplify: y = 2(x%5Elnx) ?
I took the ln of both sides and I tried bringing the lnx down by properties of log so I ended up with:
lny = lnxln2x
How do I simplify this?
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
If the problem is as you posted it, then there is nothing you can do to simplify it.

However, if the problem is actually:
y+=+2e%5E%28ln%28x%29%29
then there is something we can do. And it helps if you understand what a logarithm represents. Logarithms are exponents. In general
log%28a%2C+%28b%29%29
represents the exponent for "a" which results in "b". With your equation,
ln(x)
represents the exponent for e which results in x. And where so we find ln(x)? Answer: As an exponent on e! So
e%5E%28ln%28x%29%29+=+x
by the very definition of logarithms! So your equation simplifies to:
y = 2x