SOLUTION: Six consecutive integers are given. The sum of the second, fourth and fifth is 41. The sum of the third and sixth is:

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Question 277073: Six consecutive integers are given. The sum of the second, fourth and fifth is 41. The sum of the third and sixth is:

Answer by checkley77(12844) About Me  (Show Source):
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Let x,x+1,x+2,x+3,x+4,x+5 be the 6 integers.
x+1+x+3+x+4=41
3x+8=41
3x=41-8
3x=33
x=11 ans.
11+2+11+5
13+16=29 ans.