SOLUTION: i have no clue how to do this: -2X^3y^2(6x^2y^3+2x^2-3x^3y) the ^ means the the following # is an exponent....

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: i have no clue how to do this: -2X^3y^2(6x^2y^3+2x^2-3x^3y) the ^ means the the following # is an exponent....      Log On


   

Question 27704: i have no clue how to do this: -2X^3y^2(6x^2y^3+2x^2-3x^3y)
the ^ means the the following # is an exponent....
Answer by askmemath(368) About Me  (Show Source):
You can put this solution on YOUR website!
-2%28X%5E3%29%28y%5E2%29%286%28x%5E2%29%28y%5E3%29%2B2%28x%5E2%29-3%28x%5E3%29y%29
Phew took some editing to figure out this problem. I think all you want to do is Multiply the term outside the brackets with the terms inside the brackets
Do you know the Law of Indices
Let me explain through examples
Suppose you have%28X%5E3%29%2AX%5E2
Then you re-write as X%5E%283%2B2%29+=+X%5E5
So if you have two terms that you are mutltiplying and both have the same base i.e. X then you can just add the Indices or the Powers
for e.g.
%282%5E2%29%2A2%5E3
we know that 2%5E2+=+4 and 2%5E3+=+8 and 4%2A8=32
So ,by the law of Indices
2%5E%282%2B3%29+=+2%5E5+=+32
Now can you do it from here??