SOLUTION: The company newsletter needs to get out by the end of the workday. Karen can staple and fold all of the newsletters in 23 hours. John could do it by himself in 17 hours. Mary could
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Question 277026: The company newsletter needs to get out by the end of the workday. Karen can staple and fold all of the newsletters in 23 hours. John could do it by himself in 17 hours. Mary could do it by herself in 19 hours.
Karen begins to work, then one hour later May joins her, then two hours after that, John joins them. If Karen began stapling and folding at 8:00, will the job be done by 5:00? How long would each person have been working by the time the job is done? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The company newsletter needs to get out by the end of the workday.
Karen can staple and fold all of the newsletters in 23 hours.
John could do it by himself in 17 hours.
Mary could do it by herself in 19 hours.
Karen begins to work, then one hour later Mary joins her, then two hours after that, John joins them.
If Karen began stapling and folding at 8:00, will the job be done by 5:00?
How long would each person have been working by the time the job is done?
:
Let t = working time of John
then
(t+2) = Mary's working time
and
(t+3) = Karen's working time
;
Let the completed job = 1
: + + = 1
Multiply equation by 7429 (that's 23*17*19), clear the denominators
323(t+3) + 391(t+2) + 437t = 7429
:
323t + 969 + 391t + 782 + 437t = 7429
:
1151t + 1751 = 7429
:
1151t = 7429 - 1751
:
1151t = 5678
t -
t = 4.93 hrs is John's time
then
4.93 + 3 = 7.93 hrs is Karen's time who started at 8:00
They will finish in 7.93 hrs which is about 3:56 PM
:
Even if they took an hour for lunch they would just make it by 5.
