SOLUTION: What are the coordinates of the turning point of the graph with the equation y=3x^2+6x-1?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: What are the coordinates of the turning point of the graph with the equation y=3x^2+6x-1?      Log On


   



Question 276998: What are the coordinates of the turning point of the graph with the equation y=3x^2+6x-1?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What are the coordinates of the turning point of the graph with the equation y=3x^2+6x-1?
-------------
The vertex is at x = -b/2a = -6/6 = -1
y = -4
-->(-1,-4) is the vertex, a minimum.
Is that what you mean by "turning point?" There is no point of inflection, the 2nd derivative is 6, no sign change.