SOLUTION: {{{x^3+x^2-10x-6}}}/x-3 Can you please help me solve this? Thank you.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: {{{x^3+x^2-10x-6}}}/x-3 Can you please help me solve this? Thank you.      Log On


   



Question 276721: x%5E3%2Bx%5E2-10x-6/x-3
Can you please help me solve this? Thank you.

Found 2 solutions by jim_thompson5910, scott8148:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
In order to simplify this, we can use polynomial long division.




So the quotient is x%5E2%2B4x%2B2 and the remainder is 0. This means that %28x%5E3%2Bx%5E2-10x-6%29%2F%28x-3%29=x%5E2%2B4x%2B2%2B0%2F%28x-3%29 or more simply %28x%5E3%2Bx%5E2-10x-6%29%2F%28x-3%29=x%5E2%2B4x%2B2


Note: consequently, this means that x%5E3%2Bx%5E2-10x-6=%28x-3%29%28x%5E2%2B4x%2B2%29 (just multiply both sides by x-3)

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
it is like "long division" from grade school

x goes into x^3, x^2 times

x^2 times (x - 3) is (x^3 - 3x^2)

(x^3 + x^2) minus (x^3 -3x^2) is 4x^2 ___ bring down -10x

x goes into 4x^2, 4x times

4x times (x - 3) is (4x^2 - 12x)

(4x^2 - 10x) minus (4x^2 - 12x) is 2x ___ bring down -6

x goes into 2x, 2 times

2 times (x - 3) is (2x - 6)

(2x - 6) minus (2x - 6) is zero ___ no remainder

x%5E3%2Bx%5E2-10x-6/x-3 = x^2 + 4x + 2