SOLUTION: 5(2k+3)-2(k-8)>3(2k+4)+k-2

Algebra ->  Inequalities -> SOLUTION: 5(2k+3)-2(k-8)>3(2k+4)+k-2      Log On


   



Question 276649: 5(2k+3)-2(k-8)>3(2k+4)+k-2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

5%282k%2B3%29-2%28k-8%29%3E3%282k%2B4%29%2Bk-2 Start with the given equation.


10k%2B15-2k%2B16%3E6k%2B12%2Bk-2 Distribute.


8k%2B31%3E6k%2B12%2Bk-2 Combine like terms on the left side.


8k%2B31%3E7k%2B10 Combine like terms on the right side.


8k%3E7k%2B10-31 Subtract 31 from both sides.


8k-7k%3E10-31 Subtract 7k from both sides.


k%3E10-31 Combine like terms on the left side.


k%3E-21 Combine like terms on the right side.


----------------------------------------------------------------------
Answer:
So the solution is k%3E-21