SOLUTION: Three consecutive even integers are such that the square of the first plus the square of the third is 136. Find the three integers

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Question 276188: Three consecutive even integers are such that the square of the first plus the square of the third is 136. Find the three integers
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
n^2+(n+4)^2=136
n^2+n^2+8n+16=136
2*(n^2+4n+8)=136
n^2+4n+8=68
n^2+4n-60=0
(n+10)*(n-6)=0
n=6 n=-10
(6,8,10) and (-10,-8,-6)
6^2+10^2=136