SOLUTION: 16 decreased by the sum of twice a # and 11 20 multiplied by two fiths of a # 5 added to the difference between the 3 and eight

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Question 276022: 16 decreased by the sum of twice a # and 11
20 multiplied by two fiths of a #
5 added to the difference between the 3 and eight
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
16 decreased by the sum of twice a # and 11
16 - (2x + 11)
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20 multiplied by two fiths of a #
20(2/5)x
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5 added to the difference between the 3 and eight
(3-8) + 5
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Cheers,
Stan H.