SOLUTION: Ten identically shaped beads are randomly strung along a straight wire. 1f 3 of them are red, 2 are blue, and 5 are green, find the probability the the beads are arranged so that f

Algebra ->  Equations -> SOLUTION: Ten identically shaped beads are randomly strung along a straight wire. 1f 3 of them are red, 2 are blue, and 5 are green, find the probability the the beads are arranged so that f      Log On


   



Question 276012: Ten identically shaped beads are randomly strung along a straight wire. 1f 3 of them are red, 2 are blue, and 5 are green, find the probability the the beads are arranged so that from left to right the beads are red, then blue, then green.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Ten identically shaped beads are randomly strung along a straight wire. 1f 3 of them are red, 2 are blue, and 5 are green, find the probability the the beads are arranged so that from left to right the beads are red, then blue, then green.
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If you mean all the red followed by all the blue followed by all the green
there is only one such arrangement.
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Since all the red are indistinguishable (same for blue and for green) there
are 10!/(3!*2!*5!) possible arrangements.
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The probability of the desired arrangement is 1/(10!/(3!*2!*5!)
= (3!*2!*5!)/10!
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Cheers,
Stan H.