SOLUTION: Please help me find the illegal values of b in this fraction 2b^2 +3b -10 ___________ __ b^2 -2b -8

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Question 275887: Please help me find the illegal values of b in this fraction
2b^2 +3b -10
______________
b^2 -2b -8
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
2b^2 +3b -10
______________
b^2 -2b -8
.
b^2 -2b -8
=(b-4)(b+2) so b can't equal 4 or -2 or there will be division by zero which is not allowed.
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Ed
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graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C%282x%5E2%2B3x-10%29%2F%28x%5E2-2x-8%29%29