SOLUTION: I am not sure how to solve this: The perimeter of a rectangle is 50 centimeters. the length is 9 centimeters more than the width. Find the length and the width of the rectangle.

Algebra ->  Rectangles -> SOLUTION: I am not sure how to solve this: The perimeter of a rectangle is 50 centimeters. the length is 9 centimeters more than the width. Find the length and the width of the rectangle.      Log On


   

Question 275802: I am not sure how to solve this: The perimeter of a rectangle is 50 centimeters. the length is 9 centimeters more than the width. Find the length and the width of the rectangle.
Found 2 solutions by josmiceli, mananth:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for perimeter of a rectangle is
P+=+2L+%2B+2W
given:
P+=+50 cm
L+=+W+%2B+9 cm
Substitute this in the formula
P+=+2%2A%28W+%2B+9%29+%2B+2W
50+=+2W+%2B+18+%2B+2W
4W+=+50+-+18
4W+=+32
W+=+8
and
L+=+W+%2B+9
L+=+8+%2B9
L+=+17
The length is 17 cm and the width is 8 cm
check answer:
P+=+2%2A%28W+%2B+9%29+%2B+2W
50+=+2%2A%288+%2B+9%29+%2B+2%2A8
50+=+2%2A17+%2B+16
50+=+34+%2B+16
50+=+50
OK

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
I am not sure how to solve this: The perimeter of a rectangle is 50 centimeters. the length is 9 centimeters more than the width. Find the length and the width of the rectangle.
LET THE WIDTH BE X
the length will be 9 more than width = x+9
Perimeter = 2*l + 2*W
2*(x+9) + 2* x= 50
2x+18 +2x=50
4x= 50-18
4x=32
x= 8 cms
length= 8 +9= 17 cms