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Question 275440: The sum of two integers are 10. Three times one integer is 3 less than 8 times the other integer. Find the numbers.
I have tried 3x + 8(10 - x) - 3=10, also 3(10 - x)+ 8x - 3, I've started out on x+y=10, so if one integer is x, the other has to be (10 - x), like x + (10 - x)=10, but no answer. It seems like an easy one, can you help?
Thank you,
Alex Vargas
avargas91702@hotmail.com
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! The sum of two integers are 10. Three times one integer is 3 less than 8 times the other integer. Find the numbers.
Let the integer be x
Three times = 3x
other integer = 8*(10-x)
The difference is = 3
8*(10-x)-3x= 3
80-8x-3x=3
-11x=-77
x= -77/-11
x=7
the other number is 24
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