SOLUTION: The Monahan’s garden is 20 feet by 30 feet. They wish to lay a uniform border of pine bark around the garden. How large a strip should they lay if they only have enough bark to c
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: The Monahan’s garden is 20 feet by 30 feet. They wish to lay a uniform border of pine bark around the garden. How large a strip should they lay if they only have enough bark to c
Log On
Question 275084: The Monahan’s garden is 20 feet by 30 feet. They wish to lay a uniform border of pine bark around the garden. How large a strip should they lay if they only have enough bark to cover 360 square feet? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The Monahan’s garden is 20 feet by 30 feet.
They wish to lay a uniform border of pine bark around the garden.
How large a strip should they lay if they only have enough bark to cover 360 square feet?
:
let x = the width of the border
:
Find the area of the garden 20 * 30 = 600 sq/ft
then
The total area, border & garden: 360 + 600 = 960 sq/ft
:
the overall dimensions of border and garden: (2x+20) by 2x+30)
:
The overall area:
(2x+20) * (2x+30) = 960
FOIL
4x^2 + 60x + 40x + 600 = 960
:
4x^2 + 100x + 600 - 960 = 0
:
4x^2 + 100x - 360 = 0; our old friend, the quadratic equation
Simplify,divide by 4
x^2 + 25x - 90 = 0
Unfortunately this will not factor, Use the quadratic equation
a=1; b=25; c=-90
:
:
:
the positive solution
:
x =
x = 3.19 ft is the width of the border
:
:
Check solution on calc using 3.2 for the width
26.4 * 36.4 = 961 ~ 960;
Subtract the area of the garden: 960 - 600 = 360, the area of the border
