SOLUTION: Avoiding a collision. A car is traveling on a road that is perpendicular to a railroad track. When the car is 30 meters from the crossing, the car’s new collision detector warns

Algebra ->  Human-and-algebraic-language -> SOLUTION: Avoiding a collision. A car is traveling on a road that is perpendicular to a railroad track. When the car is 30 meters from the crossing, the car’s new collision detector warns      Log On


   



Question 274958: Avoiding a collision. A car is traveling on a road that
is perpendicular to a railroad track. When the car is
30 meters from the crossing, the car’s new collision
detector warns the driver that there is a train 50 meters
from the car and heading toward the same crossing. How
far is the train from the crossing?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A car is traveling on a road that is perpendicular to a railroad track.
When the car is 30 meters from the crossing, the car’s new collision
detector warns the driver that there is a train 50 meters from the car and heading toward the same crossing.
How far is the train from the crossing?
:
This is a pythag problem a^2 + b^2 = c^2
where
a = 30
c = 50
b = dist train is from the crossing
:
30^2 + b^2 = 50^2
b^2 = 50^2 - 30^2
b^2 = 2500 - 900
b = sqrt%281600%29
b = 40 meters from the crossing