SOLUTION: ) The equation of the line that goes through the point ( 5, 4 ) and is parallel to the line going through the points ( -5 ,2 ) and ( 3 ,5 ) can be written in the form y = mx+b wher

Algebra ->  Length-and-distance -> SOLUTION: ) The equation of the line that goes through the point ( 5, 4 ) and is parallel to the line going through the points ( -5 ,2 ) and ( 3 ,5 ) can be written in the form y = mx+b wher      Log On


   

Question 274920: ) The equation of the line that goes through the point ( 5, 4 ) and is parallel to the line going through the points ( -5 ,2 ) and ( 3 ,5 ) can be written in the form y = mx+b where
m is:
and b is:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Through ( 5, 4 ) and parallel to ( -5 ,2 ) and ( 3 ,5 ).
Y=mX+b
m=(y2-y1)/(x2-x1)
m=(5-2)/(3+5)
m=3/8 is the slope.
4=3/8*5+b
4=15/8+b
b=4-15/8
b=(32-15)/8
b=17/8 is the Y interception.
Y=3X/8+17/8 is the ans.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+3x%2F8+%2B17%2F8%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 3x/8 +17/8).