SOLUTION: If a, b, c, and d are consecutive integers such that a < b < c < d, then in terms of a, the sum a + b + d = a a+4 b 2a+3 c 3a+3 d 3a+4

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: If a, b, c, and d are consecutive integers such that a < b < c < d, then in terms of a, the sum a + b + d = a a+4 b 2a+3 c 3a+3 d 3a+4       Log On


   

Question 274832: If a, b, c, and d are consecutive integers such that a < b < c < d, then in terms of a, the sum a + b + d =
a a+4 b 2a+3 c 3a+3 d 3a+4

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If a, b, c, and d are consecutive integers with a < b < c < d, then

b=a+1, c=a+2, and d=a+3


So a%2Bb%2Bd=a%2B%28a%2B1%29%2B%28a%2B3%29=3a%2B4 which makes the answer d)