SOLUTION: I am not sure how to solve this problem. A rental car agency charges 14 per day plus 9 cents per mile to rent a car. Another agency charges 17 per day plus 5 cents per mile to rent

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: I am not sure how to solve this problem. A rental car agency charges 14 per day plus 9 cents per mile to rent a car. Another agency charges 17 per day plus 5 cents per mile to rent      Log On


   



Question 274754: I am not sure how to solve this problem. A rental car agency charges 14 per day plus 9 cents per mile to rent a car. Another agency charges 17 per day plus 5 cents per mile to rent the same car. How many miles will have to be driven in order for the cost of a car from the first agency to equal the cost of a car from the second agency? Express as a system of linear equations.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A rental car agency charges 14 per day plus 9 cents per mile to rent a car.
Another agency charges 17 per day plus 5 cents per mile to rent the same car.
How many miles will have to be driven in order for the cost of a car from the first agency to equal the cost of a car from the second agency?
:
let m =no. of miles for them to be equal
:
First agency cost equation
C = .09m + 14
:
2nd agency cost
C = .05m + 17
:
Find when they are equal
.09m + 14 = .05m + 17
:
.09m - .05m = 17 - 14
:
.04m = 3
m = 3%2F.04
m = 75 mile trip, they will be equal
;
:
You can prove this to yourself. Substitute 75 for m in both agency equations