SOLUTION: Write a polynomial function of least degree that has real coefficents, 3, -3, and 2i for the given zeroes and leading coefficents of 1.
Is the answer x3-2x2-9x-18?
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-> SOLUTION: Write a polynomial function of least degree that has real coefficents, 3, -3, and 2i for the given zeroes and leading coefficents of 1.
Is the answer x3-2x2-9x-18?
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Question 274624: Write a polynomial function of least degree that has real coefficents, 3, -3, and 2i for the given zeroes and leading coefficents of 1.
Is the answer x3-2x2-9x-18?
I started by f(x)=(x+3)(x-3)(x-2i)
(x2-9)(x-2i)=(x2-9)(x-2(1)) Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! If it has a zero of 2i it has to have a zero of -2i.
(x+3)(x-3)(x+2i)(x-2i)
=(x^2-9)(x^2-4i^2)
=(x^2-9)(x^2+4) (i^2=-1)
=x^4-5x^2-36
.
Ed
