SOLUTION: Hi. I have been stumbling with this one and I am happy to have found this site!! I shouldn't be having a problem, but I am--- road block!!!

Click here to see ALL problems on Equations

Question 274195: Hi. I have been stumbling with this one and I am happy to have found this site!! I shouldn't be having a problem, but I am--- road block!!!
- Two planes having the same airspeed depart simultaneously from the airport, flying in opposite directions. One plane flies directly into a 35mph wind, and the other flies in the same direction as the wind. After a period of time, one plane has traveled 460 miles and the other has traveled 404 miles. Let x= the airspeed of each plane (note: this is only possible because the airspeed is the same.)
I know d=rt. I have r=x-35mph for the one going to the wind and x+35mph for the other. Do I simply go 460=35t for the one going with the wind?
I am lost here and not sure if I am thinking too much on it. Thank you for your help!!!!! rl
Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website!
(x-35)t=404
(x+35)t=460
.
t=404/(x-35)
(x+35)*(404/(x-35))=460
404(x+35)=460(x-35)
404x+14140=460x-16100
-56x=-30240
x=540
.
Ed

SOLUTION: Hi. I have been stumbling with this one and I am happy to have found this site!! I shouldn't be having a problem, but I am--- road block!!! - Two planes having the same airspeed