SOLUTION: Find two consecutive odd integers such that twice the greater is 17 more than the lesser

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Question 274168: Find two consecutive odd integers such that twice the greater is 17 more than the lesser
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Let the first number be x.
The next odd number would be x + 2.
So twice the greater is 2(x + 2)...set it up and get
2(x + 2) = 17 + x
2x + 4 = 17 + x now subtract x
x + 4 = 17 now subtract 4
x = 13