SOLUTION: twice as many dimes as nickles, two more quarters than nickels and a total of $5.50

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Question 273973: twice as many dimes as nickles, two more quarters than nickels and a total of $5.50
Answer by calegebra(14) About Me  (Show Source):
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set x = number of nickels
2x = number of dimes
x + 2 = number of quarters
nickel = .05
dime = .10
quarter = .25
(.05)(x) + (.10)(2x) + (.25)(x + 2) = $5.50
.05x + .20x + .25x + .50 = $5.50
.05x + .20x + .25x = $5.00
.50x = $5.00
x = 10 number of nickels (10)(.05) = .50
2x = 20 number of dimes (20)(.10) = 2.00
x + 2 = 12 number of quarters (10 + 2) = 12 * .25 = 3.00
Add them up 3.00 + 2.00 + .50 = 5.50