SOLUTION: a ship traveling east at 25mph is 10 mi from a harbor when another ship leaves the harbor traveling east at 35mph. how long does it take the second ship to catch up to the first?

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Question 273949: a ship traveling east at 25mph is 10 mi from a harbor when another ship leaves the harbor traveling east at 35mph. how long does it take the second ship to catch up to the first?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a ship traveling east at 25mph is 10 mi from a harbor when another ship leaves the harbor traveling east at 35mph. how long does it take the second ship to catch up to the first?
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1st ship DATA:
distance: x-10 mi ; rate = 25 mph ; time = d/r = (x-10)/25 hrs.
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2nd ship DATA:
distance = x miles ; rate = 35 mph ; time = d/r = x/35 hrs.
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Equation:
time = time
(x-10)/25 = x/35
35x - 350 = 25x
10x = 350
x = 35 miles
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time = x/35 = 35/35 = 1 hr
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Cheers,
Stan H.