SOLUTION: Find three consecutive integers such that the sum of three times the first integer, one-third of the second integer, and eight times the third integer is -29.
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Question 27390: Find three consecutive integers such that the sum of three times the first integer, one-third of the second integer, and eight times the third integer is -29. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Let 1st integer be "x"
2nd is "x+1"
3rd is "x+2"
EQUATION:
3x+(1/3)(x+1)+8(x+2)=-29
Multiply through be "3" to get:
9x+(x+1)+24(x+2)=-87
9x+x+1+24x+48=-87
34x=-136
x=-4
x+1=-3
x+2=-2
Cheers,
Stan H.
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