SOLUTION: how do solve log6x-3=-4

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Question 273880: how do solve log6x-3=-4
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Is your problem
log%28%286x-3%29%29=-4
or
log%286%2C+%28x-3%29%29=-4
or
log%28%286x%29%29+-+3+=-4
or
log%286%2C+%28x%29%29+-+3+=-4?

Instead of me solving 4 equations, 3 of which you don't care about, please repost your problem using parentheses around the argument to the logarithm. And if the problem involves base 6 logarithms, just use something like:
base 6 log(x-3) = -4
or
log base 6 (x-3) = -4