24 is even, so divisible by 2.
12 is even, so divisible by 2.
6 is even, so divisible by 2.
3 is prime.
Hence,
Find the prime factorization of 441.
441 is odd, so not divisible by 2.
441 sum of digits is 12. 12 is divisible by 3, hence 441 divisible by 3.
147 sum of digits is 12, so 147 is divisible by 3. and 7 is prime.
Hence,
441 has no factors of 2. 24 has no factors of 7. 24 has one factor of 3 and 441 has 2 factors of 3. The fewest number of times 3 occurs is 1, hence the GCF is 3.
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