SOLUTION: solve tby completing the square: 4x^2-20x+21=0. Factor the polynomial

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Question 273645: solve tby completing the square: 4x^2-20x+21=0. Factor the polynomial
Found 2 solutions by richwmiller, ankor@dixie-net.com:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2-20x+21=0
x^2-5x+21/4=0
x^2-5x=-21/4
(5/2)^2
25/4
25/4 to both sides
x^2-5x=-21/4
x^2-5x+25/4=1
(x-5/2)^2=1
|x-5/2|=1
+(x-5/2)=+1
x=2/2+5/2=7/2
x-5/2=-1
x-5/2=-1
x=3/2
x=7/2 and x=3/2
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression 4x%5E2-20x%2B21, we can see that the first coefficient is 4, the second coefficient is -20, and the last term is 21.



Now multiply the first coefficient 4 by the last term 21 to get %284%29%2821%29=84.



Now the question is: what two whole numbers multiply to 84 (the previous product) and add to the second coefficient -20?



To find these two numbers, we need to list all of the factors of 84 (the previous product).



Factors of 84:

1,2,3,4,6,7,12,14,21,28,42,84

-1,-2,-3,-4,-6,-7,-12,-14,-21,-28,-42,-84



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 84.

1*84 = 84
2*42 = 84
3*28 = 84
4*21 = 84
6*14 = 84
7*12 = 84
(-1)*(-84) = 84
(-2)*(-42) = 84
(-3)*(-28) = 84
(-4)*(-21) = 84
(-6)*(-14) = 84
(-7)*(-12) = 84


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -20:



First NumberSecond NumberSum
1841+84=85
2422+42=44
3283+28=31
4214+21=25
6146+14=20
7127+12=19
-1-84-1+(-84)=-85
-2-42-2+(-42)=-44
-3-28-3+(-28)=-31
-4-21-4+(-21)=-25
-6-14-6+(-14)=-20
-7-12-7+(-12)=-19




From the table, we can see that the two numbers -6 and -14 add to -20 (the middle coefficient).



So the two numbers -6 and -14 both multiply to 84 and add to -20



Now replace the middle term -20x with -6x-14x. Remember, -6 and -14 add to -20. So this shows us that -6x-14x=-20x.



4x%5E2%2Bhighlight%28-6x-14x%29%2B21 Replace the second term -20x with -6x-14x.



%284x%5E2-6x%29%2B%28-14x%2B21%29 Group the terms into two pairs.



2x%282x-3%29%2B%28-14x%2B21%29 Factor out the GCF 2x from the first group.



2x%282x-3%29-7%282x-3%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%282x-7%29%282x-3%29 Combine like terms. Or factor out the common term 2x-3



===============================================================



Answer:



So 4%2Ax%5E2-20%2Ax%2B21 factors to %282x-7%29%282x-3%29.



In other words, 4%2Ax%5E2-20%2Ax%2B21=%282x-7%29%282x-3%29.



Note: you can check the answer by expanding %282x-7%29%282x-3%29 to get 4%2Ax%5E2-20%2Ax%2B21 or by graphing the original expression and the answer (the two graphs should be identical).


Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
solve by completing the square: 4x^2-20x+21=0. Factor the polynomial
:
4x^2 - 20x + ___ = -21
:
We need the coefficient of x^2 to be 1, divide equation 4, results:
x^2 - 5x + ____ = -21%2F4
:
To complete the square (5/2)^2 = 25/4
:
x^2 - 5x + 25%2F4 = -21%2F4 + 25%2F4
:
x^2 - 5x + 25%2F4 = 4%2F4
:
x^2 - 5x + 25%2F4 = 1
:
(x - 5%2F2)^2 = 1
Find the square root of both sides
x - 5%2F2 = +/-sqrt%281%29
two solutions
x = 5%2F2 + 1
and
x = 5%2F2 - 1
:
x = 7%2F2 and 3%2F2