Question 273644: Find the vertex of y+xsquared + 5
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the vertex of y+xsquared + 5
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I'm going to assume you meant y = x^2+5
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You have a quadratic with a = 1, b = 0, c = 5
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The vertex occurs where x = -b/2a = -0/(2) = 0
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The y-value when x = 0 is y = 0^2+5 = 5
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So the vertex is (0,5)
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Cheers,
Stan H.
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