SOLUTION: There is three consecutive positive integers. if the square of the third integer is 51 more than the sum of the first two what are the integers?
Algebra ->
Equations
-> SOLUTION: There is three consecutive positive integers. if the square of the third integer is 51 more than the sum of the first two what are the integers?
Log On
Question 273359: There is three consecutive positive integers. if the square of the third integer is 51 more than the sum of the first two what are the integers? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! LET X, X+1 & X+2 BE THE 3 INTEGERS.
(X+2)^2=X+X+1+51
X^2+4X+4=2X+52
X^2+4X-2X+4-52=0
X^2+2X-48=0
(X-6)(X+8)=0
X-6=0
X=6 ANS. FOR THE FIRST INTEGER.
6+1=7 ANS. FOR THE SECOND INTEGER.
6+2=8 FOR THE LARGEST INTEGER.
PROOF:
8^2=6+7+51
64=64
(