SOLUTION: Analyzing the motion of a projectile. A projectile is fired from a cliff 200 feet above the water at an inclination of 45 degrees to the horizontal, with a muzzle velocity of 50 fe

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Question 273349: Analyzing the motion of a projectile. A projectile is fired from a cliff 200 feet above the water at an inclination of 45 degrees to the horizontal, with a muzzle velocity of 50 feet per second. The height h of the projectile above the water is given by
h (x)= -32 x^2/ (50)^2 + x+ 200
When the height of the projectile is 100 feet above the water, how far is it from the cliff?

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Analyzing the motion of a projectile. A projectile is fired from a cliff 200 feet above the water at an inclination of 45 degrees to the horizontal, with a muzzle velocity of 50 feet per second. The height h of the projectile above the water is given by
h (x)= -32 x^2/ (50)^2 + x+ 200
When the height of the projectile is 100 feet above the water, how far is it from the cliff?
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h (x)= -32 x^2/ (50)^2 + x+ 200
Clarify the function. Is it -32x%5E2%2F50%5E2 ??
Doesn't look right.