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| Question 273272:  A number where the first two digits are the reverse of 3rd & 4th digits and the last digit is one-half of the fisrt & double of the 2nd..??
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! let x = the 1st digit (and 4th) let y = the 2nd digit (and 3rd)
 let z = the last digit
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 A number where the first two digits are the reverse of 3rd & 4th digits
 x, y, y, x, z
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 and the last digit is one-half of the first & double of the 2nd..??
 z = .5x + 2y
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 For z to be a single digit; y =< 4; x has to be an even number
 lets say y = 3, x = 4, then z = 8
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 How about 43348?
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