SOLUTION: Three standard number cubes are tossed. What is the probability that the sum of the numbers on the tops of the cubes will be 17 or greater?
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Question 273197: Three standard number cubes are tossed. What is the probability that the sum of the numbers on the tops of the cubes will be 17 or greater? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Three standard number cubes are tossed. What is the probability that the sum of the numbers on the tops of the cubes will be 17 or greater?
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ways to succeed:
666
665,656,566
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So 4 ways to succeed out of 6*6*6 = 36 possible outcomes
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Ans: 4/36 = 1/9
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Cheers,
Stan H.
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