SOLUTION: The perimeter of a rectangle is 38 inches. If the length of the rectangle is three inches more than three times the width, find the dimensions.
Algebra ->
Rectangles
-> SOLUTION: The perimeter of a rectangle is 38 inches. If the length of the rectangle is three inches more than three times the width, find the dimensions.
Log On
Question 272867: The perimeter of a rectangle is 38 inches. If the length of the rectangle is three inches more than three times the width, find the dimensions. Found 2 solutions by checkley77, JBarnum:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! L=3W+3
2L+2W=38
2(3W+3)+2W=38
6W+6+2W=38
8W=38-6
8W=32
W=32/8
W=4 ANS. FOR THE WIDTH.
L=3*4+3=12+3=15 ANS. FOR THE LENGTH.
PROOF:
2*15+2*4=38
30+8=38
38=38
You can put this solution on YOUR website! perimeter is where
if (length is three morethan three times width)
then simply use substitution solve for W add subtract divide
___________ substitute multiply add
___________
Check substitute multiply add
Correct
(