SOLUTION: The perimeter of a rectangle is 40. If its length is 2 more than 5 times its width, find the dimensions of the rectangle. My solution is -perimeter =L+W since Length is 2 mor

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Question 272736: The perimeter of a rectangle is 40. If its length is 2 more than 5 times its width, find the dimensions of the rectangle.
My solution is -perimeter =L+W
since Length is 2 more than 5 times width then length would be (5w+2)
so I was thinking 40=(2+5w) + w but the answer I get solving for w is 5 which doesn't calculate in my formula as being correct
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You need to double each dimension to get 40=2%282%2B5w%29%2B2w since the original perimeter formula is P=2L%2B2W.