SOLUTION: Please help me...I have to find the slope of the pair (-9,-9) and (7,-9)...I came up with 0/16...what is the slope? Please show me how?...Thank you I look forward to hearing from

Algebra ->  Linear-equations -> SOLUTION: Please help me...I have to find the slope of the pair (-9,-9) and (7,-9)...I came up with 0/16...what is the slope? Please show me how?...Thank you I look forward to hearing from       Log On


   



Question 272649: Please help me...I have to find the slope of the pair (-9,-9) and (7,-9)...I came up with 0/16...what is the slope? Please show me how?...Thank you I look forward to hearing from you.
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
your point pairs are:

(x1,y1) = (-9,-9)

(x2,y2) = (7,-9)

the slope is the change in the value of y divided by the change in the value of x.

the change in the value of y is y2 - y1 = (-9) - (-9) = (-9) + 9 = 0.

the change in the value of x is x2 - x1 = (7) - (-9) = (7) + (9) = 16

your slope is 0/16 = 0

I believe you have the right answer.

the slope intercept form of the equation of a straight line is:

y = mx + b

where m is the slope and b is the y intercept.

since the slope is 0, we can use either one of the 2 points to find the equation.

let's use the point (x1,y1) = (-9,-9)

since the slope is equal to 0, your equation becomes:

y = 0x + b

we let y = -9 and x = -9 to get:

-9 = 0*(-9) + b

this becomes:

-9 = b

since b is the y intercept, your equation becomes:

y = 0x - 9 which is the same as:

y = -9

graph of your equation looks like this:

graph+%28600%2C600%2C-10%2C10%2C-10%2C10%2C-9%29

what you have is a horizontal line at y = -9

if this is the equation of your line, then both points must be on that line.

your first point is (x1,y1) = (-9,-9).

look on the graph and you can see that when x = -9, y = -9.

your second point is (x2,y2) = (7,-9)

look on the graph and you can see that when x = 7, y = -9

in fact, x can be any value and y will be equal to -9.

you had it right.