SOLUTION: using substitution to solve each system of quations for x=8y-10 x=4y-5

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Question 272576: using substitution to solve each system of quations for
x=8y-10
x=4y-5
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
x=8y-10
x=4y-5
.
x - 8y = -10
x - 4y = -5
subtract
-4y = -5
y = 5/4
.
substituting
x = 8y -10
x = 8(5/4) - 10 = 0
.
Solution: (0, 5/4)
.
Check by inspecting the graphs:
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1%2F8%2Ax%2B5%2F4%2C+1%2F4%2Ax%2B5%2F4%29