SOLUTION: The equation of the line parallel to 3x-y=6 and passing through the point (3,2) is: a) y=-1/3x+1 b) y=1/3x+3 c)y=3x+7 d)y=3x+11 e) y=3x-7 I need the step by step to solve t

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Question 27237: The equation of the line parallel to 3x-y=6 and passing through the point (3,2) is:
a) y=-1/3x+1
b) y=1/3x+3
c)y=3x+7
d)y=3x+11
e) y=3x-7
I need the step by step to solve this!
Answer by rodriguezh2(15) (Show Source):
You can put this solution on YOUR website!
The first step is to put the equation 3x - y =6 into y = mx + b form.
Remember that m represents the slope of a line and b represents the y-intercept.
So we solve for y
3x - y = 6 (add y to both sides and subtract 6 from both sides)
y = 3x - 6
Now we know that y = 3x - 6 is parallel to the line we want to find. Parallel lines have the same slopes (or m values). Therefore the slope is 3 in
y = 3x - 6 and also the slope is 3 in the line we are looking for.
We also know the line we are lookin for passes through point (3,2)
[3 =x and 2 = y]
We can use the formula
(y - y1) = m(x - x1)
(y - 2) = 3(x - 3) Now solve the equation for y
(y - 2) = 3x - 9 Now add 2 to both sides
y = 3x - 7
answer (e)