Question 272250: For simplifying complex rational expressions, my testbook gives us two methods of doing it. I am having trouble understanding Method 2 which refers to:
1. Add or subtract, as necessary, to get a single rational expression in the numerator.
2. Add or subtract, as necessary, to get a single rational expression in the denominator.
3. Divide the numerator by the denpminator.
4. If possible, simplify by removing a factor of 1.
Here is my problem. please walk me thrugh it using the stated method.
x/2 + 2x/3
___________
1/x - x/2
they say the answer is 7x^2/3(2-x^2)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! x/2 + 2x/3
___________
1/x - x/2
1. Add or subtract, as necessary, to get a single rational expression in the numerator.
(x/2)+(2x/3) = (3x+4x)/6 = (7x)/6
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2. Add or subtract, as necessary, to get a single rational expression in the denominator.
(1/x)-(x/2) = (2-x^2)/2x
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3. Divide the numerator by the denpminator.
(7x/6)/(2-x^2)/2x
Invert the denominator and multiply to get:
(7x/6)(2x/(2-x^2))
4. If possible, simplify by removing a factor of 1.
(7x^2)/(3(2-x^2)
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Cheers,
Stan H.
they say the answer is 7x^2/3(2-x^2)
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