SOLUTION: two cyclists start biking from a trail 3 hours apart. the second cyclist travels a 10 miles per hour and 3 hours after cyclist who is traveling at 6 miles per hour how much time wi
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Question 272119: two cyclists start biking from a trail 3 hours apart. the second cyclist travels a 10 miles per hour and 3 hours after cyclist who is traveling at 6 miles per hour how much time will pass before the second cyclist up with the first from the time the second cyclist started biking Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! the second cyclist travels a 10 miles per hour and 3 hours after cyclist who is
traveling at 6 miles per hour how much time will pass before the second cyclist
up with the first from the time the second cyclist started biking
:
Let t = travel time of the 2nd cyclist
then
(t+3) = travel time of the 1st
:
When the 2nd cyclist catches the 1st, they will have traveled the same distance.
Write a dist equation: dist = speed * time
:
10t = 6(t+3)
10t = 6t + 18
10t - 6t = 18
4t = 18
t =
t = 4.5 hrs, the 2nd catches the 1st
;
:
Check solution by confirming they both went the same dist:
4.5(10) = 45 mi
7.5(6) = 45 mi
