SOLUTION: given the linear equation 3y = -2x +13 find the slope of a line perpendicular to the given line and the slope of a line parallel to the given line
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Question 272032: given the linear equation 3y = -2x +13 find the slope of a line perpendicular to the given line and the slope of a line parallel to the given line Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Y=mX+b is the standard line equation where m=slope & b=the Y intersection.
3y = -2x +13
y=-2x/3+13/3 this line has a slope=-2/3.
Any perpendicular line will have a slope=3/2 (the negative reciprocal).
Any parallel line will have a slope=-2/3
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