Question 271748: How many liters of 30% alcohol solution and 80% alcohol solution must be mixed to obtain 100 liters of 50% alcohol solution? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! (liters of alcohol in final solution)/(liters of final solution) = 50%
Let = liters of 30% solution to use
Let = liters of 80% solution to use
given: = liters of alcohol in 30% solution = liters of alcohol in 80% solution
-----------------------------------------------
(1)
(2)
from (1)
(1)
(1)
Multiply both sides of (2) by
and subtract from (1)
(1)
(2)
and, from (2)
60 liters of the 30% solution and 40 liters
of the 80% solution are needed
check:
(1)
OK
