SOLUTION: how to solve for all x, 36x^4-8x^3-28x^2

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Question 271731: how to solve for all x, 36x^4-8x^3-28x^2
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
First off to make this a bit more easier to confront, take out 4x^2 like this:
36x^4-8x^3-28x^2 Rewritten as:
4x^2(9x^2-2x-7) Now we can factor this to get:
4x^2(9x+7)(x-1) Solve for x we get:
x=0
x=1
x=-7/9
Plug these numbers in to see if they work.
RJ
Check out a book that might help:
www.math-unlock.com