SOLUTION: Suppose that te wideth of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
P= 2L + 2W
a) Set up an equation for the perimeter
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-> SOLUTION: Suppose that te wideth of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
P= 2L + 2W
a) Set up an equation for the perimeter
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Question 271726: Suppose that te wideth of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
P= 2L + 2W
a) Set up an equation for the perimeter incolving only L, the length of the rectangle.
84=2(3-x) + 2(x)? Is this right?
b) Solove this euation algebraicall to find the length of the rectangle, Find the width as well
You can put this solution on YOUR website! Suppose that te wideth of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
P= 2L + 2W
a) Set up an equation for the preimeter incolving lony L, the length of the rectangle.
84=2(3-x) + 2(x)? Is this right?
b) Solove this euation algebraicall to find the length of the rectangle, Find the width as well
You're on the right track. Since W = L-3 the second equation should be;
84 = 2*L + 2*(L-3)
Now you can solve the above for L then compute W = L-3.
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