SOLUTION: Three children in a family were born at a 4-year intervals. Six years ago, the sum of their ages was 18. Find the present ages of the children.
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Question 271719: Three children in a family were born at a 4-year intervals. Six years ago, the sum of their ages was 18. Find the present ages of the children. Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! a+b+c=18
b=a+4
c=b+4
c=a+8
a-6+a+4-6+a+8-6=18
3a+12-18=18
3a=24
a=8
6 years ago
a=2
b=6
c=10
so now
a=8
b=12
c=16
