SOLUTION: log(base2)(x - 2) + 5 = 8 - log(base2) 4
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Question 271571
:
log(base2)(x - 2) + 5 = 8 - log(base2) 4
Answer by
edjones(8007)
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log[2](x-2)+5=8-log[2](4)
log[2](x-2)+log[2](4)=3
2^(log[2](x-2))*2^(log[2](4))=2^3
4(x-2)=8
4x-8=8
4x=16
x=4
.
Ed