SOLUTION: 2. Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet. a) Set up an equation for the perimeter involving o

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 2. Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet. a) Set up an equation for the perimeter involving o      Log On


   

Question 271396: 2. Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
a) Set up an equation for the perimeter involving only L, the length of the rectangle.
Answer:
b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
Answer: Length _____, Width ______
Show your work here:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
W=L-3
2W+2L=84
2(L-3)+2L=84
2L-6+2L=84
4L=84+6
4L=90
L=90/4
L=22.5 ANS. FOR THE LWNGTH.
W=22.5-3=19.5 ANS. FOR THE WIDTH.
PROOF;
2*19.5+2*22.5=84
39+45=84
84=84