SOLUTION: Two jets are traveling toward each other and are 4000km apart. THe rate of one jet is 100km/h faster than the rate of the other. if the jets pass each other after 2.5 hrs., what is

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Question 271392: Two jets are traveling toward each other and are 4000km apart. THe rate of one jet is 100km/h faster than the rate of the other. if the jets pass each other after 2.5 hrs., what is the rate of the faster jet? pleaaseee i need help coming up with the equations!
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
4,000=(X+X+100)2.5
4,000=(2X+100)2.5
4,000=5X+250
5X=4,000-250
5X=3,750
X=3,750/5
X=750 KMH. SPEED OF THE SLOWER PLANE.
750+100=850 KMH SPEED OF THE FASTER PALNE.
PROOF:
4,000=(750+850)2.5
4,000=1,600*2.5
4,000=4,000