SOLUTION: The plans for an arpartment complex for 438 apartments with each apartment having one, two, or three bedrooms. There were to be 48 more three-bedroom than one-bedroom apartments an
Question 271380: The plans for an arpartment complex for 438 apartments with each apartment having one, two, or three bedrooms. There were to be 48 more three-bedroom than one-bedroom apartments and the nimber of two bedroom apartments was to be 24 less than 4 times the number of one bedroom apartments . How many apartments of each type were in the plans? Answer by Stitch(470) (Show Source):
You can put this solution on YOUR website! Set up:
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Let A = # of 1 bedroom apartments
Let B = # of 2 bedroom apartments
Let C = # of 3 bedroom apartments
Equation 1:
Equation 2:
Equation 3:
Solution:
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Notice that all the variables are in terms of A.
We can substitute the values in terms of A into equation 1
Equation 1: Rewrite the equation Combine like terms Subtract 24 from both sides Divide both sides by 6
Now plug 69 into equations 2 & 3 for A
Equation 2:
Equation 3:
Check you answers:
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Plug your values back into equation 1
Equation 1:
(